```begin;
comment  'LIBRARY' 1
;
Boolean B;
real X;
integer array A[+1 : .6⏨2];
integer I, N;
B := false;
N := ⏨+2 × .6;
X := 0;
comment
;
begin;
comment
;
own real  array C0[0 : 1];
procedure P(A, B, C);
value A;
integer A;
string B;
Boolean array C;
begin;
begin;
C[(1)] := true ∨ .8 > C0[if true then 0 else 1];
C[-(-2)] := false ∧ .4 ≥ X + 500⏨-2;

* Syntax error at: C(/.3&1/):=.3#(0)and(if&1#&4thentrueelsefalse);

* Syntax error at: iffalsethenP(A,<STRING>,C)else;

end;
;
for I := 1 step 1 until 3 do
begin;
if .3 ≤ 6 ÷ 2 then goto OUT;
OUT: ;
end;
end;
real procedure A0L;
A0L := if X < X then ⏨4 else .6;
integer procedure II;
II := +1 × (3 ÷ (4)) - ⏨2 + A0L;
begin;
Boolean array C[II + II ÷ II ÷ II : 1.0 ↑ II + 3];
C0[0] := if B ∧ (1) = (2) then 0 else 0;

* Syntax error at: P(+1)L:(<>)M:(C);

I := -N - I × N ÷ N ↑ 1;
goto if 1 - .9 = II ÷ 6 ∧ II ≤ A0L then L else L1;
L: L1: for I := I step N until II do ;
if +.3 + ⏨2 = +(.3) then B := ¬B ≡ false else B := ⏨1 > 3 ≡ true;
for I := ((1)) step +(1) until +60 do
begin;
A[⏨1 - 9] := 1 ÷ .1 - 0.1;

* Syntax error at: A(/I/):=if(true)orA(/1/)-1#A(/&1-9/)*1implfalsethen+1else-1;

end;
for I := 1,
-9 + A[1] step -9 + A[1] until .6⏨1 do
N := if +A[1] + 0 = A[1] then 0 else ⏨1 - 9 + N;

* Syntax error at: if+N#+1equivN=-Nor0<+Nand0+N>=0thenelsegotoL2;

B := B ⊃ N > +0 ≡ 0 < -A[1] ÷ ⏨1 ∨ true;
L2: goto (L3);

* Syntax error at: L3:B:=trueandfalseorfalseimpltrueequiv+0#-1;

N := 1 ↑ N × 1 + (⏨1) × ⏨-2 ↑ (1) ÷ (2) + N;
B := true ≡ -(0) ÷ 1 > -A[1] ∨ ¬true ≡ ¬true;

* Syntax error at: B:=notfalseequiv.1=1impltrueimpl0#1;

for I := 1 while true do
goto EXIT;
EXIT: for I := I while false do
if -0 ≥ +6 then for N := 1 while 0 ≥ -1 ∨ +N ≤ +(1) do
for N := 1 do ;
B := 0 < ⏨1 ⊃ +1 ≤ .1 ∨ -3 ≤ -6 ∧ true ∧ +1 ≤ ⏨1;
B := B ⊃ -(1) < (2) ≡ ⏨1 = .1 ∧ -(1) ≤ 0;
if C[1] ⊃ ¬+1 = ⏨1 then ;
X := A[1] ↑ .5 ↑ ⏨1 + (if ¬N ≥ .1 ∨ (if true then false else true) then -1 else +2);
begin;
integer procedure A0(B, C);
Boolean B, C;
A0 := if B ⊃ ¬C then (1) ↑ 2 else if C ∧ ¬B then (1) else (2);
X := X + A0(true, false) + A0(false, true ⊃ .4 < .6);
N := X × A0(¬0 = ⏨1, 1 ≥ ⏨2) - A0(¬-1 > .1, ¬.1 ≤ (1));
end;
begin;
goto L4;
L4: begin;
for I := I step if 1 < 2 then 1 else 2 until -10 do ;
end;

* Syntax error at: ififBthen.1>&1elsenot&1#.6thenbegin;

X := X + 100;
end else for I := 1 step .3⏨1 until if ¬(false) then 1 else A[1] do
B := true;
end;
B := false;
end;
begin;
real Y;
array D[C0[0] : +A[1] ÷ 1 + 1 + C0[0]];
Boolean procedure B1;
begin;
own Boolean  X;
X := if D[0] < 0 then ¬D[0] ≤ (0) ⊃ (D[0] ≥ (1)) else B;

* Syntax error at: B:=Xand&1+D(/0/)>(1)equiv(D(/0/)#0);

B1 := B ∨ ⏨1 + D[0] = D[0] ≡ (1) > D[0];
end;
switch S := L10, L11;
D[0] := 0;

* Syntax error at: B:=B1impl&1+(1)#D(/0/)andB;

L10: ;
L11: ;
;
end;
begin;
switch SS := LA, LB;
own integer  P;
procedure Q(L);
label L;
begin;
array R[(0) : -(-1)], S[1 : ⏨1];
for I := 0,
+1,
.3,
⏨1,
(2),
if B then 0 else 1 do
begin;
;
end;
for I := 1 while I + (0) ≥ 9,
I + 1 while +I < 10 do S[I] := 0;
for I := 1 + S[2] while -I > 0,
I + (1) while ¬I ≥ 10 do
if B then ;
end;
Q(LA);
LA: ;
LB: ;
;
end;
begin;
procedure P;
begin;
;
for I := 1 while if 1 < 2 then 0 = A[1] else (A[1]) > 0 do ;
end;
array D[1 : if 1 < 2 then 2 else 1];
for I := 1 while .1 < -3,
I + 1 while (I) < 3 do D[I] := I;
for I := D[2],
1 step (1) until (1) do
if 1 < 2 then L:  else begin;
;
end;
P;
for I := 1 step ⏨1 - 9 until ⏨1 - 9,
1 while ⏨1 > 11 do X := X + N;
end;
OUTREAL(99, X + N);
;
end;
end;
```